$${\int }_1^2(x+4{)}^{2}dx$$ 1) Tašo Tahana $$\begin{array}{r}{\int }_1^2(x+4{)}^{2}dx={\int }_1^2(x^2+\S \S V1(1,10,1)\S \S \S \S V0(1,8,1)\S \S x+16)dx\\ & ={[\frac{x^3}{3}+\frac{8x^2}{2}+16x]}_1^2\\ & =[\frac{8}{3}+\frac{8\ast 4}{2}+16\ast 2]-[\frac{1}{3}+\frac{8}{2}+16]\end{array}$$ 2) Oda ču im ja njima 5 - 6 večeriju ! $$\begin{array}{r}f(x)=3x^4⟹\frac{dy}{dx}=12x^3\end{array}$$ $$\begin{array}{rl}f(x)=2x^{-3/2}⟹\frac{dy}{dx}=-3x^{-5/2}& =-\frac{3}{\sqrt{x^5}}\end{array}$$ 3) Ode srati $$\begin{array}{r}x=2t+1⟹\frac{dx}{dt}=2\\ y=t^2⟹\frac{dy}{dt}=2t\\ \frac{dy}{dx}=\frac{dy}{dt}÷\frac{dx}{dt}\\ ⟹2t÷2=t\end{array}$$